Clinical social worker
Leonard Clark
LCSW
Lexington, KY
Contact for availability
From the public NPI record
- Practice location
- Lexington, KY 40503
- Registered profession
- clinical social worker
- Also registered as
- addiction (substance use disorder) counselor; social worker
- Licenses listed
- ADCLAD0022409 (Kentucky); 1498 (Kentucky)
- NPI issued
- January 8, 2007
- Record last updated
- April 25, 2019
Copied from the public NPI record for NPI 1215085600. A listed license may have changed since; check with the state licensing board.
Unclaimed profile. Not yet claimed or confirmed by this provider; details come from their public NPI record and may be out of date. How listings are kept current.
About Leonard
Leonard Clark is listed as a clinical social worker in Lexington, KY. Also registered as an addiction (substance use disorder) counselor and a social worker. Contact the practice for current services and appointment availability.
Common questions
Answers come from the public NPI record. For what to ask any provider, see Choosing a provider.
About the provider (2)
What does Leonard Clark's NPI record list?
The public NPI record (NPI 1215085600) lists Leonard Clark as a clinical social worker, gives the credential LCSW and lists licenses ADCLAD0022409 (Kentucky); 1498 (Kentucky).
Link to this answerHow can I check whether Leonard Clark's details are current?
Leonard Clark has not claimed this profile, so its details come only from the public NPI record, last updated April 25, 2019. Look up NPI 1215085600 in the NPI registry, check a license with the state licensing board and confirm details with the practice.
Link to this answerAppointments and getting started (2)
How do I request an appointment with Leonard Clark?
Call the practice at (859) 229-8160 to ask about availability and request an appointment. The practice confirms the clinician and the appointment.
Link to this answerIs Leonard Clark accepting new clients?
Not listed. Contact Leonard Clark's practice to ask whether new clients are being accepted.
Link to this answer