Psychiatric nurse practitioner
Sandra Aubrey
APRN
Elizabethtown, KY
From the public NPI record
- Practice location
- Elizabethtown, KY 42701
- Registered profession
- psychiatric/mental health nurse practitioner
- Also registered as
- psych/mental health registered nurse
- Licenses listed
- 1072504 (Kentucky); 3015725 (Kentucky)
- NPI issued
- February 15, 2007
- Record last updated
- January 25, 2021
Copied from the public NPI record for NPI 1538202817. A listed license may have changed since; check with the state licensing board.
Unclaimed profile. Not yet claimed or confirmed by this provider; details come from their public NPI record and may be out of date. How listings are kept current.
About Sandra
Sandra Aubrey is listed as a psychiatric nurse practitioner in Elizabethtown, KY. Also registered as a psych/mental health registered nurse. Contact the practice for current services and appointment availability.
Common questions
Answers come from the public NPI record. For what to ask any provider, see Choosing a provider.
About the provider (2)
What does Sandra Aubrey's NPI record list?
The public NPI record (NPI 1538202817) lists Sandra Aubrey as a psychiatric/mental health nurse practitioner, gives the credential APRN and lists licenses 1072504 (Kentucky); 3015725 (Kentucky).
Link to this answerHow can I check whether Sandra Aubrey's details are current?
Sandra Aubrey has not claimed this profile, so its details come only from the public NPI record, last updated January 25, 2021. Look up NPI 1538202817 in the NPI registry, check a license with the state licensing board and confirm details with the practice.
Link to this answerAppointments and getting started (2)
How do I request an appointment with Sandra Aubrey?
Call the practice at (270) 506-2730 to ask about availability and request an appointment. The practice confirms the clinician and the appointment.
Link to this answerIs Sandra Aubrey accepting new clients?
Not listed. Contact Sandra Aubrey's practice to ask whether new clients are being accepted.
Link to this answer